(x)=3x^2-2x-7

Solution for (x)=3x^2-2x-7 equation:

(x)=3x^2-2x-7

We move all terms to the left:

(x)-(3x^2-2x-7)=0

We get rid of parentheses

-3x^2+x+2x+7=0

We add all the numbers together, and all the variables

-3x^2+3x+7=0

a = -3; b = 3; c = +7;
Δ = b2-4ac
Δ = 32-4·(-3)·7
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{93}}{2*-3}=\frac{-3-\sqrt{93}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{93}}{2*-3}=\frac{-3+\sqrt{93}}{-6}
$